{"id":1260,"date":"2026-07-09T05:45:35","date_gmt":"2026-07-09T05:45:35","guid":{"rendered":"https:\/\/lift-cylinders.com\/?p=1260"},"modified":"2026-07-09T05:45:35","modified_gmt":"2026-07-09T05:45:35","slug":"lift-cylinder-sizing-selection-guide","status":"publish","type":"post","link":"https:\/\/lift-cylinders.com\/tr\/application\/lift-cylinder-sizing-selection-guide\/","title":{"rendered":"Asans\u00f6r Silindiri Boyutland\u0131rma ve Se\u00e7im K\u0131lavuzu"},"content":{"rendered":"
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M\u00dcHEND\u0130SL\u0130K KILAVUZU \u00b7 BOYUTLANDIRMA VE SE\u00c7\u0130M \u00b7 H\u0130DROL\u0130K KALDIRMA S\u0130L\u0130ND\u0130RLER\u0130<\/span><\/p>\n

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Asans\u00f6r Silindiri Boyutland\u0131rmas\u0131
\n& Se\u00e7im K\u0131lavuzu
\nKuvvet \u00b7 \u00c7ap \u00b7 Strok Hesaplamas\u0131<\/span><\/h1>\n

Yanl\u0131\u015f silindir \u00e7ap\u0131 se\u00e7imi, kald\u0131rma silindiri spesifikasyonunda yap\u0131lan en pahal\u0131 hatad\u0131r; \u00e7ok k\u00fc\u00e7\u00fck bir silindir gerekli kuvveti \u00fcretemez; \u00e7ok b\u00fcy\u00fck bir silindir ise enerji israf\u0131na yol a\u00e7ar ve daha b\u00fcy\u00fck, daha pahal\u0131 bir hidrolik g\u00fc\u00e7 \u00fcnitesi gerektirir. Bu k\u0131lavuz, y\u00fck analizi, kuvvet hesaplamas\u0131, silindir \u00e7ap\u0131 se\u00e7imi, strok belirleme ve bas\u0131n\u00e7 derecelendirmesi dahil olmak \u00fczere eksiksiz boyutland\u0131rma metodolojisini, en yayg\u0131n uygulama t\u00fcrleri i\u00e7in \u00f6rneklerle birlikte ele almaktad\u0131r.<\/p>\n

Kuvvet Hesaplamas\u0131<\/span>
\nDelik Se\u00e7imi<\/span>
\nG\u00fcvenlik Fakt\u00f6rleri<\/span><\/div>\n

KALDIRMA S\u0130L\u0130ND\u0130RLER\u0130 \u00b7 BOYUTLANDIRMA M\u00dcHEND\u0130SL\u0130\u011e\u0130 \u00b7 TEMMUZ 2026<\/p>\n<\/div>\n<\/header>\n

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REFERANS \u00b7 TEMEL BEDEN \u00d6L\u00c7\u00dc FORM\u00dcLLER\u0130NE B\u0130R BAKI\u015e<\/p>\n

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UZATMA KUVVET\u0130<\/p>\n

F = P \u00d7 \u03c0\/4 \u00d7 D\u00b2<\/p>\n

F = kuvvet (N), P = bas\u0131n\u00e7 (Pa), D = delik \u00e7ap\u0131 (m)<\/p>\n<\/div>\n

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GER\u0130 \u00c7EKME KUVVET\u0130<\/p>\n

F = P \u00d7 \u03c0\/4 \u00d7 (D\u00b2\u2212d\u00b2)<\/p>\n

d = \u00e7ubuk \u00e7ap\u0131 \u2014 halka alan\u0131, delik alan\u0131ndan daha k\u00fc\u00e7\u00fckt\u00fcr.<\/p>\n<\/div>\n

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GEREKL\u0130 \u00c7AP<\/p>\n

D = \u221a(4F \/ \u03c0\u00d7P)<\/p>\n

Minimum i\u00e7 \u00e7ap\u0131 bulun \u2014 bir \u00fcst standart boyuta yuvarlay\u0131n<\/p>\n<\/div>\n

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AKI\u015e HIZI<\/p>\n

Q = A \u00d7 v<\/p>\n

Q = ak\u0131\u015f h\u0131z\u0131 (m\u00b3\/s), A = delik alan\u0131 (m\u00b2), v = \u00e7ubuk h\u0131z\u0131 (m\/s)<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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